Hmm...

{integral} 1/sinx dx

I got is ln tanx...

cos differentiate sinx is cos x and integrate 1/sinx would be ln sinx...

haha.... so eventually is (ln sinx)/(cos x) and thus ln tanx

XD.... I know it must be wrong.... but thats how I see it...

for {integral} 1/cosx dx

I thought will get (-ln cos x)/(sin x) ?

LOL...

cos differentiate cosx is -sin x.... how dya get 1-sinx??